1100p-10p^2=0

Solution for 1100p-10p^2=0 equation:

1100p-10p^2=0

a = -10; b = 1100; c = 0;
Δ = b2-4ac
Δ = 11002-4·(-10)·0
Δ = 1210000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1210000}=1100$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1100)-1100}{2*-10}=\frac{-2200}{-20}
=+110
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1100)+1100}{2*-10}=\frac{0}{-20}
=0
$